In this example, the known, fixed, value was the R. And based on the given spec that it was a 60 watt, 240 volt bulb, we know its value is 960 ohms.
Then, we mutilied the voltage by ½, so power is multiplied by (½)² , which is ¼ . The resulting current at any point in this exercise was the result of the fixed resistance and the GIVEN voltage.
Linear Mode
